4X^2+3x+1=5

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Solution for 4X^2+3x+1=5 equation:


Simplifying
4X2 + 3x + 1 = 5

Reorder the terms:
1 + 4X2 + 3x = 5

Solving
1 + 4X2 + 3x = 5

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 4X2 + -1 + 3x = 5 + -1

Reorder the terms:
1 + -1 + 4X2 + 3x = 5 + -1

Combine like terms: 1 + -1 = 0
0 + 4X2 + 3x = 5 + -1
4X2 + 3x = 5 + -1

Combine like terms: 5 + -1 = 4
4X2 + 3x = 4

Add '-3x' to each side of the equation.
4X2 + 3x + -3x = 4 + -3x

Combine like terms: 3x + -3x = 0
4X2 + 0 = 4 + -3x
4X2 = 4 + -3x

Divide each side by '4'.
X2 = 1 + -0.75x

Simplifying
X2 = 1 + -0.75x

Reorder the terms:
-1 + X2 + 0.75x = 1 + -0.75x + -1 + 0.75x

Reorder the terms:
-1 + X2 + 0.75x = 1 + -1 + -0.75x + 0.75x

Combine like terms: 1 + -1 = 0
-1 + X2 + 0.75x = 0 + -0.75x + 0.75x
-1 + X2 + 0.75x = -0.75x + 0.75x

Combine like terms: -0.75x + 0.75x = 0.00
-1 + X2 + 0.75x = 0.00

The solution to this equation could not be determined.

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